## Algebra Solver Fractions

**Introduction :**

A fraction (from the Latin fractus, broken) is a number that can represent part of a whole. The earliest fractions were reciprocals of integers: ancient symbols representing one part of two, one part of three, one part of four, and so on. A much later development were the common or "vulgar" fractions which are still used today (½, ⅝, ¾, etc.) and which consist of a numerator and a denominator

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**Source : Wikipedia)**

Algebra Solver Fractions - Additions:

**Fractions Solver:**

The followings are some of the examples of algebra solver fractions for additions.

**Addition of fractions: `3/4 + 9/7` .**

**Solution:**

Find a LCM for the denominators in the given fractions.

The LCM of 4, 7 = 28

So `(3*4)/(4*7)` = `12/28`

` (9*7)/(7*4)` = ` 63/28`

The denominators are equal then we can add the numerator in the given fractions.

= `12/28+63/28`

= `(12+63)/28`

= `75/28` is the solution.

**Simplify the fractions: `(5x)/11+(10x)/8` .**

**Solution:**

The given fractions are

= `(5x)/11+(10x)/8`

LCD for the denominators 11 and 8 is 88.

= `(8*5x)/88+(11*10x)/88`

To express the denominators in the LCD form as

= `(40x)/88+(110x)/88`

We can simplify the numerators.

= `(40x+110x)/88`

We can add the numerators.

= `(150x)/88`

Algebra Solver Fractions - Subtractions:

The followings are some of the examples of algebra solver fractions for subtractions.

**Subtractions of fractions: `3/4 - 9/7` .**

**Solution:**

Find a LCM for the denominators in the given fractions.

The LCM of 4, 7 = 28

So `(3*4)/(4*7) ` = `12/28`

`(9*7)/(7*4)` = `63/28`

The denominators are equal then we can subtract the numerator in the given fractions.

= `12/28-63/28`

= `(12-63)/28`

= `-51/28` is the solution.

**Simplify fraction : `(5x)/11-(10x)/8` .**

**Solution:**

The given fractions are

= `(5x)/11-(10x)/8`

LCD for the denominators 11 and 8 is 88.

= `(8*5x)/88-(11*10x)/88`

To express the denominators in the LCD form as

= `(40x)/88-(110x)/88`

We can simplify the numerators.

= `(40x-110x)/88`

We can subtract the numerators.

= `(-70x)/88`